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How can I prevent a function from being called too frequently in JavaScript?

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How can I prevent a function from being called too frequently in JavaScript?

Asked on Feb 12, 2026

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To prevent a function from being called too frequently, you can use a technique called "debouncing". Debouncing ensures that a function is only executed after a specified delay has passed since the last time it was invoked.

<!-- BEGIN COPY / PASTE -->
        function debounce(func, delay) {
            let timeoutId;
            return function(...args) {
                clearTimeout(timeoutId);
                timeoutId = setTimeout(() => {
                    func.apply(this, args);
                }, delay);
            };
        }

        const logMessage = () => console.log("Function executed!");
        const debouncedLogMessage = debounce(logMessage, 300);

        // Example usage: Call debouncedLogMessage multiple times
        debouncedLogMessage();
        debouncedLogMessage();
        debouncedLogMessage();
        // "Function executed!" will only be logged once, 300ms after the last call
        <!-- END COPY / PASTE -->

Additional Comment:

The "debounce" function takes two arguments: the function to debounce ("func") and the delay in milliseconds ("delay").
"timeoutId" is used to store the ID of the timeout, allowing it to be cleared if the function is called again before the delay.
"func.apply(this, args)" ensures the original function is called with the correct context and arguments.
In the example, "debouncedLogMessage" is called multiple times, but "logMessage" will only execute once, 300 milliseconds after the last invocation.

✅ Answered with JavaScript best practices.

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How can I prevent a function from being called too frequently in JavaScript?

Asked on Feb 12, 2026

Answer

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