This question explores JavaScript and addresses practical considerations related to: How does the Array.filter() method work?

The Array.filter() method creates a new array with all elements that pass the test implemented by the provided function. It does not modify the original array. const numbers = [1, 2, 3, 4, 5]; const evenNumbers = numbers.filter(number => number % 2 === 0); console.log(evenNumbers); // Output: [2, 4] ADDITIONAL COMMENT: - The filter method takes a callback function as an argument. - The callback function is called once for each element in the array. - If the callback returns true, the element is included in the new array. - The original array remains unchanged. ✅

How does the Array.filter() method work?

Ask any question about JavaScript here... and get an instant response.

Post this Question & Answer:

How does the Array.filter() method work?

Asked on Jul 20, 2025

Answer

Previous Question Next Question

The Array.filter() method creates a new array with all elements that pass the test implemented by the provided function. It does not modify the original array.

<!-- BEGIN COPY / PASTE -->
        const numbers = [1, 2, 3, 4, 5];
        const evenNumbers = numbers.filter(number => number % 2 === 0);

        console.log(evenNumbers); // Output: [2, 4]
        <!-- END COPY / PASTE -->

Additional Comment:

The filter method takes a callback function as an argument.
The callback function is called once for each element in the array.
If the callback returns true, the element is included in the new array.
The original array remains unchanged.

✅ Answered with JavaScript best practices.

Ask any question about JavaScript here... and get an instant response.

How does the Array.filter() method work?

Asked on Jul 20, 2025

Answer

Real Questions. Clear Answers.